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x^2=15x+105
We move all terms to the left:
x^2-(15x+105)=0
We get rid of parentheses
x^2-15x-105=0
a = 1; b = -15; c = -105;
Δ = b2-4ac
Δ = -152-4·1·(-105)
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{645}}{2*1}=\frac{15-\sqrt{645}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{645}}{2*1}=\frac{15+\sqrt{645}}{2} $
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